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    化学:化学习题

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    If you were to magnifya cell 10,000 fold (which is typical of the magnification that is using a microscope), how big would it appear? Assume you are viewing a "typical" eukaryotic cell with a cellular diameter of 50 microns.

    如果把细胞放大10000倍(显微镜的典型放大倍数)将会有多大?假设一个典型的真核细胞的直径为50微米。,

    属类:化学及生命科学-化学-化学习题

    If this cell were a muscle cell, how many molecules of actin could it hold assuming there were no other cellular components present?

    如这个细胞是肌细胞,假定没有其它细胞组分存在,它能容纳多少个肌动蛋白分子。

    属类:化学及生命科学-化学-化学习题

    Actin molecules are spherical with a diameter of 3.6 nm; assume the muscle cell is spherical. The volume of a sphere is 4/3πr3.

    假定肌动蛋白分子为球形,直径3.6nm;肌细胞也是球形的,球体的体积为4/3πr3

    属类:化学及生命科学-化学-化学习题

    If this were a liver cell of the same dimensions, how many mitochondria could it hold assuming there were no other cellular components present?

    如这个同样大小的细胞为肝细胞,如没有其它细胞组分存在,它能容纳多少个线粒体?

    属类:化学及生命科学-化学-化学习题

    Assume mitochondria are spherical with a diameter of 1.5μm; assume the liver cell is spherical.

    假定线粒体为球形,直径为1.5μm;肝细胞也是球形的。

    属类:化学及生命科学-化学-化学习题

    Glucose is the major energy-yielding nutrient for most cells. Assuming it is present at a concentration of 1 mM, calculate how many molecules of glucose would be present in our hypothetical (and spherical)eukaryotic cell?

    葡萄糖是大多数细胞的主要产能物质。假定其在细胞中的浓度为1mM,计算有多少个分子的葡萄糖存在于这个假定为球形的真核细胞中。

    属类:化学及生命科学-化学-化学习题

    Hexokinase is an important enzyme in the metabolism of glucose by cells. If the molar concentration of hexokinase in our eukaryotic cell is 20μM, how many glucose molecules are available for each hexokinase enzyme molecule to metabolize?

    己糖激酶是细胞代谢葡萄糖的一个重要的酶。如果其在真核细胞中的摩尔浓度为μM,每个己糖激酶分子能够代谢多少个葡萄糖分子?

    属类:化学及生命科学-化学-化学习题

    E. coli cells are rod-shaped, about 2 μm long and 0.8μm in diameter. The volume of a cylinder isπr2h, where h is the height of the cylinder.

    大肠杆菌为杆状,长2μm,直径为0.8μm。此圆柱体的体积为πr2h(h为其高)。

    属类:化学及生命科学-化学-化学习题

    If the average density of E coli (mostly water)is 1.1 × 103 g/L, what is the mass of a single cell?

    如果大肠杆菌的平均密度为1.1×103g/L(其中大部分为水),一个大肠杆菌的质量是多少?

    属类:化学及生命科学-化学-化学习题

    The protective cell wall of E. coli is 10 nm thick. What percentage of the total volume of the bacterium does the wall occupy?

    大肠杆菌的保护性的细胞壁厚度为10nm,细胞壁占细胞总体积的百分比是多少?

    属类:化学及生命科学-化学-化学习题

    E. coli is capable of growing and multiplying rapidly because of the inclusion in each cell of some 15,000 spherical ribosomes, which carry out protein synthesis. What percentage of the total cell volume do the ribosomes occupy?

    大肠杆菌能够迅速生长繁殖,是由于其每个细胞中有大约15,000个球形的核糖体进行蛋白质生物合成。核糖体占细胞总体积的百分比是多少?

    属类:化学及生命科学-化学-化学习题

    The genetic information contained in DNA consists of a linear sequence of successive coding units, known as codons.

    DNA中的遗传信息是由连续的编码单位即密码子的线形序列构成的。

    属类:化学及生命科学-化学-化学习题

    Each codon is a specific sequence of three nucleotides (three nucleotide pairs in double-stranded DNA), and each codon codes for a single amino acid unit in a protein.

    每个密码子是特异的三核苷酸序列(双链DNA状况下为三个三核苷酸对),每个密码子编码蛋白质的一个氨基酸单位。

    属类:化学及生命科学-化学-化学习题

    The molecular weight of an E. coli DNA molecule is about 3.1 X 109. The average molecular weight of a nucleotide pair is 660, and each nucleotide pair contributes 0.34 nm to the length of DNA.

    大肠杆菌的DNA分子的分子量为3.1×109,核苷酸对的平均分子量为660,每个核苷酸对DNA长度上的贡献为0.34nm。

    属类:化学及生命科学-化学-化学习题

    Calculate the length of an E. coli DNA molecule. Compare the length of the DNA molecule with the cell dimensions.

    计算大肠杆菌的DNA分子的长度,并与其细胞大小比较)。

    属类:化学及生命科学-化学-化学习题

    How does the DNA molecule fit into the cell?

    DNA分子是如何装配在细胞中的?

    属类:化学及生命科学-化学-化学习题

    Assume that the average protein in E. coli consists of a chain of 400 amino acids. What is the maximum number of proteins that can be coded by an E. coli DNA molecule?

    假定平均大肠杆菌细胞中的蛋白质由400个氨基酸组成,大肠杆菌DNA分子能编码的蛋白质数量最大是多少?

    属类:化学及生命科学-化学-化学习题

    Bacterial cells have a much higher rate of metabolism than animal cells. Under ideal conditions some bacteria will double in size and divide in 20 min, whereas most animal cells under rapid growth conditions require 24 h.

    细菌细胞有比动物细胞高得多的代谢速率,在理想条件下,某些细菌能在20分钟内增加一倍,而大多数动物细胞在快速生长条件下需要24小时。

    属类:化学及生命科学-化学-化学习题

    The high rate of bacterial metabolism requires a high ratio of surface area to cell volume.

    细菌的高代谢速度要求高的表/体比。

    属类:化学及生命科学-化学-化学习题

    Why would the surface-to-volume ratio have an effect on the maximum rate of metabolism?

    为何表/体比对代谢速率有影响?

    属类:化学及生命科学-化学-化学习题

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